One more shot at explaining why I think this should work. This system (that is BW's system) is based on a trigger of a combination of High with Odd or Even and Low with Odd or Even. There are 9 numbers for each combination so a trigger is satisfied when one of the other 9 numbers shows before another trigger happens.
There are only 8 numbers that are Red and Even and 10 numbers that are Red and Odd. With Black, there are 8 numbers that are Black and Odd and 10 numbers that are Black and Even. So, if we get a Red and Even trigger, the trigger is harder to develop because we only have 8 instead of 9 numbers the form this trigger. Since we win when we have a Red and Odd number hit before we get another Red and Even number and we have 10 Red and Odd numbers, we should have just a slight advantage over playing High with Odd or Even against Low wit Odd or Even.
This may be erroneous logic but it seems accurate if the system works using triggers made up of 9 numbers with a winner made by 9 numbers.
There are only 8 numbers that are Red and Even and 10 numbers that are Red and Odd. With Black, there are 8 numbers that are Black and Odd and 10 numbers that are Black and Even. So, if we get a Red and Even trigger, the trigger is harder to develop because we only have 8 instead of 9 numbers the form this trigger. Since we win when we have a Red and Odd number hit before we get another Red and Even number and we have 10 Red and Odd numbers, we should have just a slight advantage over playing High with Odd or Even against Low wit Odd or Even.
This may be erroneous logic but it seems accurate if the system works using triggers made up of 9 numbers with a winner made by 9 numbers.