So, in the case described above I'm looking among all those 6 ECs for EC that has most hits and bet its opposite. If there are 2 ECs with most hits, then between these 2 ECs I'm looking for the EC whose appearance was more recent and bet its opposite, right? But what to do in a case when I have 2 ECs with most hits and both of them hit in the last spin?
No that's not what I was told.
take the 6 even chances.. Keep a running total of the session. Doesn't matter how long the session is...
so spin 1 3 even chances are at 1 and the other 3 are at zero..
keep adding the even chance till spin 37
After spin 37 now find the lowest count if 2 even chances produce the same lowest count pick the one that has slept the most.
Keep the tally going so if at spin 37 RED was lowest bet RED if at spin 40 Even is low now bet even.
Betting is 1 unit for the start and any reset to 1 after a new high.
Progression goes up only after the 37 cycle.
If in between 37 spin cycle you reach a new high you drop to 1 unit and carry on the same cycle.
so if you are betting 4 units and third spin of that cycle you bet 33 more spins with 1 unit and increase bet at the end of that cycle.